React - Cannot read property 'map' of undefined
March 12, 2020 - 5 min read
If you are a react developer, there is a good chance that you faced this error couple of times:
TypeError: Cannot read property ‘map’ of undefined
TL;DR - If you are not in the mode for reading or you just want the bottom line, then here it is
The problem
In order to understand what are the possible solutions, lets first understand what is the exact issue here.
Consider this code block:
// Just a data fetching function
const fetchURL = "https://jsonplaceholder.typicode.com/todos/";
const getItems = () => fetch(fetchURL).then(res => res.json());
function App() {
const [items, setItems] = useState();
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
return (
<div>
{items.map(item => (
<div key={item.id}>{item.title}</div>
))}
</div>
);
}
We have a component that manage a state of items
, it also have an effect which inside it we run an asynchronous operation - getItems
, which will return us the data
we need from the server, then we call setItems
with the received data as items
.
This component also renders the items
- it iterate over it with .map
and returning a react element for each item.
But we wont see anything on the screen, well except the error:
TypeError: Cannot read property ‘map’ of undefined
What’s going on here?
We do have an items
variable:
const [items, setItems] = useState();
And we did populate it with our data returned from the server:
useEffect(() => {
getItems().then(data => setItems(data)); }, []);
Well lets examine how the react flow looks like in our example:
- React renders (invoking) our component.
- React “see” the
useState
call and return us[undefined, fn]
. - React evaluate our return statement, when it hits the
items.map(...)
line its actually runningundefined.map(...)
which is obviously an error in JavaScript.
What about our useEffect
call though?
React will run all effects after the render is committed to the screen, which means we can’t avoid a first render without our data.
Possible solutions
#1 Initial value
One possible solution is to give your variable a default initial value, with useState
it would look like that:
const [items, setItems] = useState([]);
This means that when react runs our useState([])
call, it will return us with
[[], fn]
Which means that in the first render of our component, react will “see” our items
as an empty array, so instead of running undefined.map(...)
like before, it will run [].map(...)
.
#2 Conditional rendering
Another possible solution is to conditionally render the items
, meaning if
we have the items then render them, else
don’t render (or render something else).
When working with JSX
we can’t just throw some if
else
statements inside our tree:
// ⚠️ wont work!!
export default function App() {
// ....
return (
<div>
{
if(items){ items.map(item => ( <div key={item.id}>{item.title}</div> )) } }
</div>
);
}
But instead we can create a variable outside our tree and populate it conditionally:
Note that we removed the initial array for items
.
function App() {
const [items, setItems] = useState();
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
let itemsToRender; if (items) { itemsToRender = items.map(item => { return <div key={item.id}>{item.title}</div>; }); }
return <div>{itemsToRender}</div>;}
The undefined
or null
values are ignored inside the context of JSX
so its safe to pass it on for the first render.
We could also use an else
statement if we want to render something else like a spinner or some text:
function App() {
const [items, setItems] = useState();
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
let itemsToRender;
if (items) {
itemsToRender = items.map(item => {
return <div key={item.id}>{item.title}</div>;
});
} else { itemsToRender = "Loading..."; }
return <div>{itemsToRender}</div>;
}
#2.5 Inline conditional rendering
Another option to conditionally render something in react, is to use the &&
logical operator:
function App() {
const [items, setItems] = useState();
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
return (
<div>
{items && items.map(item => { return <div key={item.id}>{item.title}</div>; })} </div>
);
}
Why it works? The react docs explains it well:
It works because in JavaScript, true && expression always evaluates to expression, and false && expression always evaluates to false. Therefore, if the condition is true, the element right after && will appear in the output. If it is false, React will ignore and skip it.
We can also use the conditional operator condition ? true : false
if we want to render the Loading...
text:
function App() {
const [items, setItems] = useState();
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
return (
<div>
{items ? items.map(item => { return <div key={item.id}>{item.title}</div>; }) : "Loading..."} </div>
);
}
We can also mix both solutions, i.e: initial value with conditional rendering:
function App() {
const [items, setItems] = useState([]);
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
return (
<div>
{items && items.length > 0 ? items.map(item => { return <div key={item.id}>{item.title}</div>; }) : "Loading..."} </div>
);
}
Though keep in mind, whenever conditions become too complex, it might be a signal for us to extract that logic to a component:
function List({ items, fallback }) { if (!items || items.length === 0) { return fallback; } else { return items.map(item => { return <div key={item.id}>{item.title}</div>; }); }}
function App() {
const [items, setItems] = useState([]);
useEffect(() => {
getItems().then(data => setItems(data));
}, []);
return (
<div>
<List items={items} fallback={"Loading..."} /> </div>
);
}
Wrapping up
When we get such an error, we are probably getting the value in an asynchronous way. We should provide an initial value for our variable or conditionally render it or both. If our condition become too complex, it might be a good time to extract the logic to a component.
Hope you found this article helpful, if you have a different approach or any suggestions i would love to hear about them, you can tweet or DM me @sag1v. 🤓